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Derivatives in AP Calculus AB

Introduction to Derivatives

A derivative is a fundamental concept in AP Calculus AB that describes how a function changes as its input changes. In simple terms, derivatives measure the instantaneous rate of change of one quantity with respect to another — for example, how fast distance changes with time.

Differential calculus is based on derivatives, and they are used in physics, economics, biology, engineering, and many other fields. They help with questions like:

Understanding the Rate of Change

The derivative measures the rate of change of a function y = f(x) with respect to x. If an infinitesimal change in x is represented by dx and the corresponding change in y is dy, the derivative is written as: \frac{dy}{dx} \quad \text{or} \quad f'(x)

This notation means the derivative of y with respect to x.

Limit Definition of a Derivative

The formal definition of the derivative is based on first principles.

f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h}

 This is called the difference quotient, and it shows how the function's average rate of change gets closer to the instantaneous rate of change as h gets smaller.

Geometric Interpretation (Graphical View)

The slope of the tangent line at a point on a graph is the same as the derivative at that point. The tangent line only touches the curve at one point, and it shows which way the function is changing.

Basic Derivative Formulas

Once you understand the limit definition, you can use derivative formulas to differentiate common functions quickly:

Solved Examples (Step-by-Step)

Example 1: Power Rule

Find: \frac{d}{dx}(x^3)
Solution:
Using the power rule,

\frac{d}{dx}(x^3)=3x^2

Thus the derivative is 3x^2.

Example 2: Linear Function

Given: f(x) = 5x^2 - 2x + 6

Find: f'(x)

Solution:
Differentiate term by term using the power rule and constant rule:
Using the power rule,

\frac{d}{dx}(5x^2) = 10x, \quad \frac{d}{dx}(-2x) = -2, \quad \frac{d}{dx}(6) = 0

So, f'(x) = 10x - 2.

Example 3: Trigonometric Function

Find: \frac{d}{dx}(\tan x)
Solution:
Start with the identity \tan x = \frac{\sin x}{\cos x}.

Using the quotient rule:

\qquad \qquad \qquad \qquad \frac{d}{dx}(\tan x) = \sec^2 x.

Therefore, \frac{d}{dx}(\tan x) = \sec^{2}x.

Example 4: Water Tank Problem

A water tank is being drained. The volume of water V (in liters) remaining after t minutes is given by: V(t) = 5000 - 20t^2. How fast is the water draining out at t = 5 minutes?
Solution:
The rate of change of volume is represented by the derivative of the function V(t).

V'(t) = \frac{d}{dt}(5000) - \frac{d}{dt}(20t^2)

V'(t) = 0 - 20(2t) = -40t.

Substitute t = 5 into the derivative function to find the rate at 5 minutes:V'(5) = -40(5) = -200

After 5 minutes, the water is draining at a rate of 200 L/min.

Higher-Order Derivatives

Trigonometric Derivative Formulas

Key Properties and Tips

Final Thoughts