Differential calculus is based on derivatives, and they are used in physics, economics, biology, engineering, and many other fields. They help with questions like:
This notation means the derivative of y with respect to x.
f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h}
\frac{d}{dx}(x^3)=3x^2
Thus the derivative is 3x^2.
Find: f'(x)
\frac{d}{dx}(5x^2) = 10x, \quad \frac{d}{dx}(-2x) = -2, \quad \frac{d}{dx}(6) = 0
So, f'(x) = 10x - 2.
Using the quotient rule:
\qquad \qquad \qquad \qquad \frac{d}{dx}(\tan x) = \sec^2 x.
Therefore, \frac{d}{dx}(\tan x) = \sec^{2}x.
V'(t) = \frac{d}{dt}(5000) - \frac{d}{dt}(20t^2)
V'(t) = 0 - 20(2t) = -40t.
Substitute t = 5 into the derivative function to find the rate at 5 minutes:V'(5) = -40(5) = -200
After 5 minutes, the water is draining at a rate of 200 L/min.